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{2х+у=8 {2х-у=0 решите систему уравнений графическим способом Посмотреть ответы NNNLLL54 NNNLLL54 Ответ: Строим прямые по точкам. Для построения прямой достаточно знать две точки, через которые проходит прямая . у=8-2х  ,      x | 2 | 3 |              y=2x  ,    x | 0 | 2 |                     y | 4 | 2 |                              y | 0 | 4 |   Прямые пересекаются в точке М(2;4) . Значит решением системы является пара чисел  (2;4) . помогите с гемотрии Можешь пожалуйста ответить на последние вопросы в профиле semenkosvatoslav semenkosvatoslav Відповідь: {2х+у=8                    {2х-у=0 {y=8-2x {y=2x-0 y=8-2x                y=2x-0 x  0  1  2             x  0  1  2 y  8  6  4            y  0  2  4 потом четришь точки, соединяешь одной линией первые три, потом второй линией вторые три и у тебя точка пересечения (2;4) Новые вопросы в Алгебра Вирішіть завдання з фото написати з розвязанням СРОЧНО!!!! Як називається ця формула: (a-b-c)²=a²+b²+c²-2ab+2bc-2ac?​ СРОЧНО!!! Як називається ця формула (a + b + c)² = a²+ b² + c² +2ab + 2bc + 2ac ​ Як називається ця формула: (a-b-c)²=a²+b²+c²-2ab+2bc-2ac?​ Предыдущий Следующий Вместе мы знаем больше Этот сайт использует cookies Политика Cookies . Вы можете указать условия хранения и доступ к cookies в своем браузере. 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Answer 1

Давайте решим эту систему уравнений графическим способом. Для этого нам нужно построить графики обеих прямых и найти точку их пересечения, которая и будет решением системы.

Первое уравнение: $2x + y = 8$

Для построения его графика, давайте найдем две точки, через которые проходит эта прямая. Мы можем это сделать, подставив различные значения для $x$ и находя соответствующие значения для $y$.

1. При $x = 2$: $2 \cdot 2 + y = 8 \Rightarrow 4 + y = 8 \Rightarrow y = 8 - 4 = 4$
2. При $x = 3$: $2 \cdot 3 + y = 8 \Rightarrow 6 + y = 8 \Rightarrow y = 8 - 6 = 2$

Таким образом, у нас есть две точки для первой прямой: (2, 4) и (3, 2).

Второе уравнение: $2x - y = 0$

Аналогично, найдем две точки для второй прямой:

1. При $x = 0$: $2 \cdot 0 - y = 0 \Rightarrow -y = 0 \Rightarrow y = 0$
2. При $x = 2$: $2 \cdot 2 - y = 0 \Rightarrow 4 - y = 0 \Rightarrow y = 4$

Таким образом, для второй прямой у нас есть точки: (0, 0) и (2, 4).

Теперь давайте построим графики этих двух прямых на координатной плоскости и найдем их пересечение:

scssCopy code
График первой прямой (2x + y = 8) проходит через точки (2, 4) и (3, 2).
График второй прямой (2x - y = 0) проходит через точки (0, 0) и (2, 4).

Теперь нарисуем их на координатной плоскости:

scssCopy code
  |
4 |       * (2,4)
  |             /\
  |            /  \
2 |   * (3,2) /    \ * (0,0)
  |           /      \
  |          /        \
  +-------------------------
    0   1   2   3   4   5

Прямые пересекаются в точке (2, 4). Таким образом, решением системы уравнений является пара чисел (2, 4).