Question

Arcsin 1\2+arccos 1

Answer 1

$arcsin \frac{1}{2}+arccos1= \frac{ \pi }{6}+2 \pi=\frac{ \pi }{6}+\frac{12 \pi }{6}=\frac{ 13\pi }{6}$

Answer 2

To calculate the values of arcsin(1/2) + arccos(1), you can use the properties of inverse trigonometric functions and their respective values.

1. First, find the value of arcsin(1/2): The arcsin(1/2) represents the angle whose sine is 1/2. This angle is pi/6 (π/6) radians or 30 degrees. So, arcsin(1/2) = π/6 or 30 degrees.

2. Next, find the value of arccos(1): The arccos(1) represents the angle whose cosine is 1. This angle is 0 radians or 0 degrees. So, arccos(1) = 0.

3. Add the two values together: π/6 + 0 = π/6

So, arcsin(1/2) + arccos(1) = π/6 radians or approximately 30 degrees.