Question

1)x^8+x^4+1=2)x^4+x^2y^2+y^4=3)a^3-3a+2=4)x^3+3x^2-4=

Answer 1

Вот примерно так ))))))))

Answer 2

You've presented four different equations. I'll provide some information about each one:

1. x^8 + x^4 + 1 = 2: This is a polynomial equation. To solve it, you can subtract 2 from both sides to get:

x^8 + x^4 - 1 = 0

This is a polynomial of degree 8. There are methods to solve such equations, but they can be complex and may not have simple analytical solutions. Numerical methods or computer algebra systems may be needed to find approximate solutions.

2. x^4 + x^2y^2 + y^4 = 3: This equation is a polynomial equation involving two variables, x and y. You can rearrange it as follows:

x^4 + x^2y^2 + y^4 - 3 = 0

This is a polynomial of degree 4 in both x and y. Solving it for specific values may require numerical methods or special techniques depending on the context of the problem.

3. a^3 - 3a + 2 = 0: This is a cubic equation in the variable a. You can solve it by factoring, the rational root theorem, or numerical methods. In this case, the equation can be factored as:

(a^3 - 3a + 2) = (a - 2)(a^2 + 2a - 1) = 0

So the solutions are a = 2 and the solutions of the quadratic equation a^2 + 2a - 1 = 0, which can be found using the quadratic formula.

4. x^3 + 3x^2 - 4 = 0: This is also a cubic equation in the variable x. You can solve it using factoring, the rational root theorem, or numerical methods. Factoring this equation is not straightforward, so numerical methods or solving it using the rational root theorem (checking for rational solutions) may be the most practical approach.

For more precise solutions or specific values, you may need to use numerical methods like the Newton-Raphson method or graphing the equations to find approximate solutions.