Question

A 7-3*(x-1)=2x b (x+4)²=x*(x+3)

Answer 1

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Готово!!Удачи:)))

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Answer 2

$a)7 - 3 \times (x - 1) = 2x \\ \\ 7 - 3x + 3 = 2x \\ \\ - 3x - 2x = - 10 \\ \\ - 5x = - 10 \\ \\ x = - 10 \div ( - 5) \\ \\ x = 2 \\ \\ \\ \\ \\ b)(x + 4) {}^{2} = x \times (x + 3) \\ \\ x {}^{2} + 8x + 16 = x {}^{2} + 3x \\ \\ x {}^{2} + 8x + 16 - x {}^{2} - 3x = 0 \\ \\ 8x - 3x = - 16 \\ \\ 5x = - 16 \\ \\ x = - \frac{16}{5} \\ \\ x = - 3 \frac{1}{5}$

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Answer 3

Let's solve these equations step by step:

Equation A: $7 - 3(x - 1) = 2x$

First, distribute the 3 inside the parentheses:

$7 - 3x + 3 = 2x$

Combine like terms:

$10 - 3x = 2x$

Now, move the $2x$ term to the left side by subtracting $2x$ from both sides:

$10 - 3x - 2x = 0$

$-5x + 10 = 0$

Now, isolate $x$ by subtracting 10 from both sides:

$-5x = -10$

Divide by -5:

$x = 2$

Equation B: $(x + 4)^2 = x(x + 3)$

Expand the left side:

$x^2 + 8x + 16 = x^2 + 3x$

Move all terms to one side:

$x^2 + 8x + 16 - x^2 - 3x = 0$

Simplify:

$5x + 16 = 0$

Now, isolate $x$ by subtracting 16 from both sides:

$5x = -16$

Divide by 5:

$x = -\frac{16}{5}$