Question

A (X - 5)(2x + 6) = 0​

Answer 1

Если произведение равно нулю, то хотя бы один из множителей равен нулю.

Уравнение квадратное, максимум

будет два корня.

Способ 1.

х-5 = 0

2х+6 = 0

2х = -6

х = -3

х1 = 5

х2 = -3.

Способ 2.

Раскроем все скобки.

(х-5)(2х+6) = 2х^2-10х+6x-30 = 2x^2-4x-30.

Прописываем коэффиценты, решаем через дискриминант.

а = 2

b = -4

c = -30

D = b^2-4*a*c = 100+156 = 256

√D = 16

x1 = -b+√D/2*a = 20/4 = 5

x2 = -b-√D/2*a = -12/4 = -3.

Answer 2

Ответ:

x1 = -3; x2 =5

Объяснение:

x-5=0

2x+6=0

x=5

x=-3

Answer 3

To solve the equation (X - 5)(2X + 6) = 0, you can use the zero-product property, which states that if the product of two factors equals zero, then at least one of the factors must be equal to zero.

So, in this case, you have:

1. X - 5 = 0
2. 2X + 6 = 0

Now, solve each equation separately:

1. X - 5 = 0: Add 5 to both sides of the equation: X = 5

2. 2X + 6 = 0: Subtract 6 from both sides of the equation: 2X = -6

   Now, divide both sides by 2 to isolate X: X = -6 / 2 X = -3

So, the solutions to the equation (X - 5)(2X + 6) = 0 are X = 5 and X = -3.