Question

2xy^2x^3 - 3xyxy 8x^2y^2x^2 - 14 записать в стандартном виде многочлен.

Answer 1

2xy^2x^3-3xyxy+8x^2y^2x^2-14 = 2x^4y^2-3x^2y^2+8x^4y^2-14 = 10x^4y^2-3^2y^2-14

Answer 2

Standard Form of a Polynomial

To write the polynomial 2xy^2x^3 - 3xyxy + 8x^2y^2x^2 - 14 in standard form, we need to arrange the terms in descending order of their exponents.

Let's break down the given polynomial and rearrange it:

1. 2xy^2x^3: - The term contains three variables: x, y, and y^2. - The exponents of the variables are 3, 1, and 2, respectively. - Rearranging the terms in descending order of their exponents, we get: 2x^3y^2.

2. - 3xyxy: - The term contains four variables: x, y, x, and y. - The exponents of the variables are 1, 1, 1, and 1, respectively. - Rearranging the terms in descending order of their exponents, we get: - 3x^2y^2.

3. + 8x^2y^2x^2: - The term contains three variables: x, y, and x. - The exponents of the variables are 2, 2, and 2, respectively. - Rearranging the terms in descending order of their exponents, we get: 8x^2y^2x^2.

4. - 14: - This is a constant term and does not contain any variables. - The constant term remains the same: - 14.

Putting it all together, the polynomial 2xy^2x^3 - 3xyxy + 8x^2y^2x^2 - 14 in standard form is:

2x^3y^2 - 3x^2y^2 + 8x^2y^2x^2 - 14.

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