Question

√1-2x-1/3 + √2x-x/3-2/15( 1-2x-1/3 - под корнем; 2x-x/3-2/15 - подкорнем)SOS!!!

Answer 1

Объяснение:

вот не знаю точно правильно ли

Answer 2

It seems like you have an expression involving square roots and fractions that you'd like to simplify. Let's break it down step by step.

The expression you've given is as follows:

√(1 - 2x - 1/3) + √(2x - x/3 - 2/15)

We can simplify this by dealing with each square root separately:

1. Simplify the first square root: √(1 - 2x - 1/3)

2. Simplify the second square root: √(2x - x/3 - 2/15)

Now, let's work on simplifying each of these square roots:

1. √(1 - 2x - 1/3): First, find a common denominator for 1 and 1/3, which is 3. So, you have: √((3/3) - (6x/3) - (1/3))

   Combine the fractions under the square root: √((3 - 6x - 1)/3)

   Simplify the numerator: √((2 - 6x)/3)

2. √(2x - x/3 - 2/15): First, find a common denominator for x/3 and 2/15, which is 15. So, you have: √((30x/15) - (5x/15) - (2/15))

   Combine the fractions under the square root: √((30x - 5x - 2)/15)

   Simplify the numerator: √((25x - 2)/15)

Now, you have simplified versions of both square roots:

1. √((2 - 6x)/3)
2. √((25x - 2)/15)

These are the simplified forms of the original expression. If you have any further operations or simplifications you'd like to perform, please specify, and I'll be happy to assist you further.