Question

(x-2)(x+2)=3(x+4)^2-2x(x+5)

Answer 1

Ответ: ответ в вложение

Объяснение:

Answer 2

To solve the equation $(x-2)(x+2) = 3(x+4)^2 - 2x(x+5)$, you can follow these steps:

1. Expand both sides of the equation:

   $(x^2 - 4) = 3(x^2 + 8x + 16) - 2x^2 - 10x$

2. Distribute the constants on the right side:

   $x^2 - 4 = 3x^2 + 24x + 48 - 2x^2 - 10x$

3. Combine like terms on the right side:

   $x^2 - 4 = x^2 + 14x + 48$

4. Subtract $x^2$ from both sides to isolate the $x$ terms:

   $-4 = 14x + 48$

5. Subtract 48 from both sides:

   $-4 - 48 = 14x$

   $-52 = 14x$

6. Finally, divide both sides by 14 to solve for $x$:

   $x = -52/14$

Simplify the fraction:

$x = -26/7$

So, the solution to the equation is $x = -26/7$.