Question

1. х-(5х+4) /2-(7х-3)/3= -12. - 2(х+21)+3(14-х) = -5х​

Answer 1

Объяснение:

Ответ на 1-ый пример, постарался подробно расписать всё

Answer 2

To solve the system of equations:

1. х - (5х + 4)/2 - (7х - 3)/3 = -12
2. -2(х + 21) + 3(14 - х) = -5х

We'll start by simplifying and solving each equation separately.

For the first equation:

х - (5х + 4)/2 - (7х - 3)/3 = -12

Let's find a common denominator for the fractions, which is 6:

6х - 3(5х + 4) - 2(7х - 3) = -12 * 6

Now, distribute and simplify:

6х - 15х - 12 - 14х + 6 = -72

Combine like terms:

-23х - 6 = -72

Now, isolate -23х:

-23х = -72 + 6 -23х = -66

Divide by -23 to solve for х:

х = -66 / -23 х ≈ 2.8696

Now, let's move on to the second equation:

-2(х + 21) + 3(14 - х) = -5х

Distribute and simplify:

-2х - 42 + 42 - 3х = -5х

Combine like terms:

-2х - 3х = -5х

Now, we have:

-5х = -5х

This equation is an identity, meaning it's true for all values of х. Therefore, there are infinitely many solutions for this system of equations, and any value of х will satisfy both equations.