Question

(х+5)²=64+(х-3)(х+3)​

Answer 1

Ответ:

$x^{2}$+10x+25=64+$x^{2}$-9

$x^{2}$-$x^{2}$+10x=64-9-25

10x=30

x=3

Объяснение:

Answer 2

Ответ:

х²+10x+25=64+-9

х²-х²+10x=64-9-25

10x=30

x=3

Объяснение:

Answer 3

To solve the equation (x + 5)² = 64 + (x - 3)(x + 3), you can start by expanding both sides of the equation and then simplifying:

(x + 5)² = 64 + (x - 3)(x + 3)

First, expand the left side by using the square of a binomial formula:

(x + 5)(x + 5) = 64 + (x - 3)(x + 3)

Now, expand both sides of the equation:

x² + 10x + 25 = 64 + (x² - 9)

Next, distribute (x² - 9) on the right side of the equation:

x² + 10x + 25 = 64 + x² - 9

Now, let's simplify the equation by moving all terms to one side:

x² + 10x + 25 - 64 - x² + 9 = 0

Now, simplify the terms:

10x + 25 - 64 + 9 = 0

Combine like terms:

10x - 30 = 0

Now, isolate x by moving -30 to the other side of the equation:

10x = 30

Now, divide both sides by 10 to solve for x:

x = 30 / 10

x = 3

So, the solution to the equation is x = 3.