Question

2y-2y^2/y-8=y/xy-x:y/y^2-1=a+b/a-b+a/b=​

Answer 1

Ответ:

1)2y-2y^2/y-8=-16y/y-8

2)y/xy-x:y/y^2-1=1-x^2y-x/x

3)a+b/a-b+a/b=a^2b+b^2-ab^2+a^2/ab

1)$\frac{2y(y-8)-2^{2} }{y-8}$           2)$\frac{1}{x} -x*\frac{y^{2} }{y} -1$          3)$\frac{a}{1} +\frac{b*b}{ba} -\frac{b}{1} +\frac{a*a}{ab}$

 $\frac{2y ^{2} -16y-2y^{2} }{y-8}$            $\frac{1}{x} -xy-1$                   $\frac{a ^{2}b }{ab} +\frac{b ^{2} }{ab} -\frac{ab^{2} }{ab} +\frac{a^{2} }{ab}$

  $-\frac{16y}{y-8}$                    $\frac{1-x^{2} y-x}{x}$                       $\frac{a^{2} b+b^{2}-ab ^{2} +a^{2} }{ab}$

Answer 2

It seems like you've provided a series of equations, but they are not clear or properly formatted. To assist you further, could you please provide more context or clarify the equations you need help with? Specifically, it would be helpful if you could:

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