Question

4*1/9³-(1+2*1/9)(2*1/9²-1/9)=​

Answer 1

=4/9-(1+2/9)(2×1/81-1/9)=4/9-11/9-(2/81-1/9)=4/9-11/9×(-7/81)=4/9+77/729=401/729

Answer 2

Ответ:

Надеюсь помогла

Удачи

Answer 3

To simplify the given expression, follow the order of operations (PEMDAS/BODMAS):

1. First, calculate the exponent: 9³ = 729.

2. Next, perform the multiplications and divisions from left to right:

4 * (1/729) - (1 + 2 * (1/9)) * (2 * (1/81) - (1/9))

3. Continue simplifying:

(4/729) - (1 + (2/9)) * ((2/81) - (1/9))

4. Simplify further:

(4/729) - (1 + (2/9)) * ((2/81) - (9/81))

5. Combine the fractions in the second part:

(4/729) - (1 + (2/9)) * (-7/81)

6. Distribute the -(1 + (2/9)) term:

(4/729) - (-7/81 - (14/81))

7. Subtract the fractions:

(4/729) + (7/81 + 14/81)

8. Find a common denominator for the fractions in the second part:

(4/729) + (21/81)

9. Simplify the fractions further:

(4/729) + (7/27)

10. Find a common denominator for the fractions:

(4/729) + (243/729)

11. Add the fractions:

(4 + 243) / 729

12. Calculate the sum:

247 / 729

So, the simplified value of the expression is 247/729.