Question

1) (8+2x)^2=2) (9-x)^2=3) (3a-6b)^2=4) (x+1)^25) (2x-5)(5+2x)=​

Answer 1

Ответ:

1) 2(4+х^2)

2) х^2 - 18х+81

3)9а^2 - 36аb+36b^2

4) x^2+2x+ 1

5) 4x^2 - 25

Answer 2

Sure, let's solve each of these equations:

1. $(8 + 2x)^2$

Expanding the square: $(8 + 2x)^2 = (8 + 2x)(8 + 2x) = 64 + 16x + 16x + 4x^2 = 4x^2 + 32x + 64$

So, $(8 + 2x)^2 = 4x^2 + 32x + 64$

2. $(9 - x)^2$

Expanding the square: $(9 - x)^2 = (9 - x)(9 - x) = 81 - 9x - 9x + x^2 = x^2 - 18x + 81$

So, $(9 - x)^2 = x^2 - 18x + 81$

3. $(3a - 6b)^2$

Expanding the square: $(3a - 6b)^2 = (3a - 6b)(3a - 6b) = 9a^2 - 18ab - 18ab + 36b^2 = 9a^2 - 36ab + 36b^2$

So, $(3a - 6b)^2 = 9a^2 - 36ab + 36b^2$

4. $(x + 1)^2$

Expanding the square: $(x + 1)^2 = (x + 1)(x + 1) = x^2 + x + x + 1 = x^2 + 2x + 1$

So, $(x + 1)^2 = x^2 + 2x + 1$

5. $(2x - 5)(5 + 2x)$

Expanding using the distributive property: $(2x - 5)(5 + 2x) = 10x + 4x^2 - 25$

Rearranging the terms: $4x^2 + 10x - 25$

So, $(2x - 5)(5 + 2x) = 4x^2 + 10x - 25$