Question

(a²-x²)²+(2ax)²=(a²+x²)²​

Answer 1

Ответ:

Если что то не так сори, сделано на скорую руку

Объяснение:

Answer 2

To solve the equation $(a^2 - x^2)^2 + (2ax)^2 = (a^2 + x^2)^2$, you can start by simplifying it step by step.

1. Expand each of the squares: $(a^2 - x^2)^2 = a^4 - 2a^2x^2 + x^4$ $(2ax)^2 = 4a^2x^2$ $(a^2 + x^2)^2 = a^4 + 2a^2x^2 + x^4$

2. Now, substitute these expanded expressions back into the original equation: $a^4 - 2a^2x^2 + x^4 + 4a^2x^2 = a^4 + 2a^2x^2 + x^4$

3. Next, simplify the equation by canceling out like terms: $a^4 + 2a^2x^2 + x^4 + 4a^2x^2 = a^4 + 2a^2x^2 + x^4$

4. Now, subtract $a^4 + 2a^2x^2 + x^4$ from both sides of the equation to isolate the $4a^2x^2$ term on the left side: $4a^2x^2 = 0$

5. Finally, divide both sides by $4a^2$ to solve for $x^2$: $x^2 = 0$

6. Take the square root of both sides to find $x$: $x = 0$

So, the solution to the equation $(a^2 - x^2)^2 + (2ax)^2 = (a^2 + x^2)^2$ is $x = 0$.