Question

(3у-1)(у+3)+2(у-1)=3у²+5​

Answer 1

Ответ: y=1

(3у-1)(у+3)+2(у-1)=3у²+5​

3$y^{2}$+9y-y-3+2y-2=3$y^{2}$+5

9y-y-3+2y-2=5

10y-5=5

10y=10

y=1

Answer 2

раскроем скобки, соберем все слева, упростим левую часть . Получим.

(3у-1)(у+3)+2(у-1)=3у²+5​

3у²+9у-у-3+2у-2=3у²+5​

3у²+9у-у-3+2у-2-3у²-5​=0

10у=10

у=10/10

у=1

Проверка

(3*1-1)(1+3)+2(1-1)=3*1²+5​

2*4+0=8

8=8

Ответ у=1

Answer 3

Let's simplify the expression step by step:

(3у-1)(у+3) + 2(у-1)

First, use the distributive property to multiply each term in the first parentheses by each term in the second parentheses:

= (3у * у + 3у * 3 - 1 * у - 1 * 3) + 2(у-1)

Now, simplify each of these multiplications:

= (3у² + 9у - у - 3) + 2(у-1)

Combine like terms within the parentheses:

= (3у² + 8у - 3) + 2(у-1)

Now, distribute the 2 into the second set of parentheses:

= 3у² + 8у - 3 + 2у - 2

Combine like terms again:

= 3у² + (8у + 2у) - 3 - 2

= 3у² + 10у - 5

So, the simplified expression is 3у² + 10у - 5.