Question

(4х-5)(2х+1)-3х(3-2х)=0 ​

Answer 1

Ответ:

Вот

Объяснение:

x1=15-✓505/28

x2=15+✓505/28

Answer 2

To solve the equation (4x - 5)(2x + 1) - 3x(3 - 2x) = 0, you can follow these steps:

1. Expand and simplify the left side of the equation:

(4x - 5)(2x + 1) - 3x(3 - 2x)

Expand both parts:

(8x^2 + 4x - 10x - 5) - (9x - 6x^2)

Simplify:

8x^2 + 4x - 10x - 5 - 9x + 6x^2

Now, combine like terms:

(8x^2 + 6x^2) + (4x - 10x - 9x) - 5

14x^2 - 15x - 5

2. Set the equation equal to zero:

14x^2 - 15x - 5 = 0

3. To solve for x, you can use the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

In this case, a = 14, b = -15, and c = -5. Plug these values into the quadratic formula:

x = (15 ± √((-15)² - 4 * 14 * (-5))) / (2 * 14)

x = (15 ± √(225 + 280)) / 28

x = (15 ± √505) / 28

4. The solutions for x are:

x₁ = (15 + √505) / 28 x₂ = (15 - √505) / 28

These are the two solutions to the equation (4x - 5)(2x + 1) - 3x(3 - 2x) = 0.