Question

- 2) 0,5x + y = 3; 4) 0,2x - 0,4y = 2.​

Answer 1

Ответ:

2) 0,5x =3-y

x = 6-2y

4) 0,2x-0, 4y =2

0,2x=2+0, 4y

x=10+2y

Answer 2

It seems like you've provided two linear equations:

1. 0.5x + y = 3
2. 0.2x - 0.4y = 2

These are a system of two linear equations with two variables (x and y). You can solve this system of equations using various methods, such as substitution or elimination. Here, I'll use the elimination method:

Let's first manipulate equation (2) to eliminate the decimal fractions by multiplying both sides by 10 to clear the decimals:

2. 2x - 4y = 20

Now, you can use the elimination method to solve this system of equations. The goal is to add or subtract the equations to eliminate one of the variables. In this case, we can eliminate y by adding the equations together:

(0.5x + y) + (2x - 4y) = 3 + 20

Now, simplify:

2.5x - 3y = 23

Now, you have a new equation:

3. 2.5x - 3y = 23

You have a system of two equations:

1. 0.5x + y = 3
2. 2.5x - 3y = 23

You can now solve this system using either the substitution method or the elimination method. If you have a preference for one of these methods, please let me know, and I can guide you through the solution using that method.