Question

381.2)(x+7c)2=25b6+70b3c+49c2​

Answer 1

Объяснение:

(х + 7с)² = х*х + 2*х*7с + 7с*7с =

х² + 14сх + 49с²

25в⁶ + 70в³с + 49с² = (5в³ + 7с)²

Answer 2

It looks like you've provided an equation:

(381.2)(x + 7c)^2 = 25b6 + 70b3c + 49c^2

This equation contains variables x, b, and c. To solve for x in terms of b and c, we can follow these steps:

1. Expand the square on the left-hand side: 381.2 * (x^2 + 14cx + 49c^2) = 25b6 + 70b3c + 49c^2

2. Distribute the 381.2 on the left-hand side: 381.2x^2 + 5476.8cx + 19082.8c^2 = 25b6 + 70b3c + 49c^2

3. Move all terms to one side to set the equation equal to zero: 381.2x^2 + 5476.8cx + 19082.8c^2 - 25b6 - 70b3c - 49c^2 = 0

4. This is now a quadratic equation in terms of x. To solve for x, you can use the quadratic formula:

   x = (-b ± √(b^2 - 4ac)) / (2a)

   In this case, a = 381.2, b = 5476.8c, and c = 19082.8c^2 - 25b6 - 70b3c - 49c^2. Plug these values into the quadratic formula to find the solutions for x. Keep in mind that the solutions may depend on the values of b and c, and it might not always be possible to find real solutions depending on the values of these variables.