Question

(*+*)²=*+4ab+4b² 64b³+*+*+*=(*+c)³

Answer 1

Ответ:

Объяснение:

Квадрат суммы (a+b)²=a²+2ab+b²

(a+2b)²=a²+2·a·2b+4b²=a²+4ab+4b²

Куб суммы (a+b)³=a³+3a²b+3ab²+b³

64b³=(4b)³

(4b)³+3·(4b)²·c+3·4b·c²+c³=64b³+48b²c+12bc²+c³=(4b+c)³

Answer 2

It seems like you're working with algebraic expressions and trying to manipulate them. Let's break down the expression step by step:

(+)² = ² + 2() + *² (Using the formula for squaring a binomial: (a + b)² = a² + 2ab + b²) = ² + 2() + *²

Now, we have 64b³ + * + * + * = (* + c)³

Let's replace * + * + * with the result from our previous step:

64b³ + 2(*) + ² = ( + c)³

Now, let's simplify the expression:

2() can be written as 2.

64b³ + 2* + ² = ( + c)³

Now, if you want to solve for * in terms of b and c, you can try to factor or expand further, but it's not clear how you'd like to simplify this expression. If you have specific values for b and c, you can substitute them in to find the value of *.

If you have a specific question or need further clarification, please provide more details, and I'll be happy to assist you.