Question

(x-1) (x²+x+1)+ x²= x²(x + 1) - 2x​

Answer 1

Ответ:

Объяснение:

(x-1) (x²+x+1) - это разность кубов

(x-1) (x²+x+1) = х³ - 1. Тогда

х³ - 1 + х² = х³ + х² - 2х

2х = 1 → х = 1/2 = 0,5

Answer 2

Ответ:

(x-1)*(x² + x+1) + x² = x² * (x +1) - 2x

x³ -1+x²=x³+x² - 2x

-1=-2x

-2х=-1

x = 0,5

Answer 3

Let's solve the equation step by step:

$(x-1)(x^2+x+1) + x^2 = x^2(x+1) - 2x$

First, expand the expressions on both sides of the equation:

$(x-1)(x^2+x+1) = x^3 + x^2 + x - x^2 - x - 1$

$x^3 + x^2 + x - x^2 - x - 1 + x^2 = x^2(x+1) - 2x$

Now, simplify the equation:

$x^3 + x - x - 1 + x^2 = x^3 + x^2 - 2x$

Next, simplify further:

$x^3 - 1 + x^2 = x^3 + x^2 - 2x$

Now, let's move all terms to one side of the equation:

$x^3 - x^3 + x^2 - x^2 + 2x - x - 1 = 0$

Simplify:

$2x - x - 1 = 0$

Combine like terms:

$x - 1 = 0$

Now, isolate x:

$x = 1$

So, the solution to the equation is $x = 1$.