Question

X^2 : x+1 = 2x+3 : x+1

Answer 1

Ответ:...

Объяснение:

Answer 2

To solve the proportion $\frac{x^2}{x+1} = \frac{2x+3}{x+1}$, you can start by multiplying both sides of the equation by $x+1$ to eliminate the denominators:

$(x+1) \cdot \frac{x^2}{x+1} = (x+1) \cdot \frac{2x+3}{x+1}$

Now, simplify both sides of the equation:

$x^2 = 2x + 3$

Next, move all the terms to one side of the equation to set it equal to zero:

$x^2 - 2x - 3 = 0$

Now, you have a quadratic equation. To solve for $x$, you can factor it or use the quadratic formula. In this case, I'll factor it:

$(x-3)(x+1) = 0$

Now, set each factor equal to zero:

1. $x - 3 = 0$ Solve for $x$: $x = 3$

2. $x + 1 = 0$ Solve for $x$: $x = -1$

So, the equation $\frac{x^2}{x+1} = \frac{2x+3}{x+1}$ has two solutions: $x = 3$ and $x = -1$.