Question

A c-2=4c+8;6) 4(x + 2) + 3 = 2x - 5 ;

Answer 1

It looks like you have two equations:

1. c - 2 = 4c + 8
2. 4(x + 2) + 3 = 2x - 5

Let's solve them one by one:

1. c - 2 = 4c + 8

First, let's isolate the variable "c" on one side of the equation. Start by subtracting "c" from both sides:

-c - 2 = 4c + 8

Now, move all terms involving "c" to one side by adding "c" to both sides:

-2 = 5c + 8

Next, subtract 8 from both sides:

-2 - 8 = 5c

-10 = 5c

Now, divide both sides by 5 to solve for "c":

(-10) / 5 = c

c = -2

So, the solution to the first equation is c = -2.

2. 4(x + 2) + 3 = 2x - 5

Let's simplify and solve for "x" in the second equation:

Start by distributing the 4 on the left side:

4x + 8 + 3 = 2x - 5

Now, combine like terms on each side of the equation:

4x + 11 = 2x - 5

Next, move the terms involving "x" to one side by subtracting 2x from both sides:

4x - 2x + 11 = -5

Now, simplify further:

2x + 11 = -5

Subtract 11 from both sides:

2x + 11 - 11 = -5 - 11

2x = -16

Finally, divide both sides by 2 to solve for "x":

(2x) / 2 = (-16) / 2

x = -8

So, the solution to the second equation is x = -8.

Therefore, the solutions to the two equations are:

1. c = -2
2. x = -8