Question

3^log 3 7= 2log 4 16 - 5log 7 (1/49)=

Answer 1

3^log(3) 7 = тройки  сокрщаються остаеться 7

 

2log 4  16  -5 log 7  (1/49)   =2*2-5*-2=4+10=14   

Answer 2

3^log 3 7=7

ответ 7

 

2log 4 16 - 5log 7 (1/49)= 2*2log 4 4 - 5log 7 7^-2= 2*2log 4 4 - (-2)*5log 7 7= 4+5= 4 +10=14

ответ 14

Answer 3

To solve this equation, let's break it down step by step:

1. $3^{\log_3 7}$:

   • Since $\log_a a = 1$ for any positive $a$, we have $\log_3 3 = 1$.
   • So, $3^{\log_3 7} = 7$.

2. $2 \cdot \log_4 16$:

   • Again, $\log_a a = 1$ for any positive $a$, so $\log_4 4 = 1$.
   • Also, $4^2 = 16$, so $\log_4 16 = 2$.
   • $2 \cdot 2 = 4$.

3. $5 \cdot \log_7 \left(\frac{1}{49}\right)$:

   • We know that $7^2 = 49$, so $\log_7 49 = 2$.
   • $\frac{1}{49} = 7^{-2}$, so $\log_7 \left(\frac{1}{49}\right) = -2$.
   • $5 \cdot (-2) = -10$.

Putting it all together:

$7 - 4 - 10 = -7$

Therefore, $3^{\log_3 7} - 2 \cdot \log_4 16 - 5 \cdot \log_7 \left(\frac{1}{49}\right) = -7$.