Question

(a+8b)//(a^2-64b^2)=

Answer 1

$\frac{a+8b}{a^2-64b^2} =\frac{a+8b}{(a-8b)(a+8b)} =\frac{1}{a-8b}$

Answer 2

$\frac{a+8b}{a^2-64b^2}=\frac{a+8b}{(a-8b)(a+8b)}=\frac{1}{a-8b}$

Answer 3

To simplify the expression $\frac{{a + 8b}}{{a^2 - 64b^2}}$, we can first factor the denominator, which is a difference of squares:

$a^2 - 64b^2 = (a + 8b)(a - 8b)$.

Now, we can rewrite the expression with the factored denominator:

$\frac{{a + 8b}}{{a^2 - 64b^2}} = \frac{{a + 8b}}{{(a + 8b)(a - 8b)}}$.

Next, we can cancel out the common factor of $(a + 8b)$ in the numerator and denominator:

$\frac{{\cancel{a + 8b}}}{{\cancel{(a + 8b)}(a - 8b)}}$.

This simplifies to:

$\frac{1}{{a - 8b}}$.

So, $\frac{a + 8b}{a^2 - 64b^2} = \frac{1}{a - 8b}$.