Question

(√x - 4)(x2+9x-10)=0

Answer 1

(√х -4)(х²+9х-10)=0
х≥0
√х-4=0             х²+9х-10=0
√х=4                Д=9²-4*(-10)=81+40=121
х=16                х₁=-9-11=-10 - не подходит, т. к. <0
                               2
                       x₂=-9+11=1
                                2
Ответ: 1; 16.

Answer 2

(x-2)(x+2)(x2+9x-10)=0
x=2
x=-2
x2+9x-10=0
D=81-4×(-10)=121
корень из 121=11
x1=(-9+11)/2=1
x2=(-9-11)/2=-10
ответ:2;-2;1;-10

Answer 3

To solve the equation (√x - 4)(x^2 + 9x - 10) = 0, you can use the zero-product property, which states that if the product of two factors is equal to zero, then at least one of the factors must be equal to zero. So, you can set each factor equal to zero and solve for x separately.

1. Set √x - 4 = 0:

√x = 4

Now, square both sides to eliminate the square root:

x = 4^2

x = 16

2. Set x^2 + 9x - 10 = 0:

You can factor the quadratic equation:

(x + 10)(x - 1) = 0

Now, set each factor equal to zero:

x + 10 = 0 x - 1 = 0

Solve for x in each equation:

For x + 10 = 0: x = -10

For x - 1 = 0: x = 1

So, there are three solutions to the equation (√x - 4)(x^2 + 9x - 10) = 0:

x = 16, x = -10, and x = 1.