Question

Y=sinx - cosx , x0=p/4

Answer 1

Y' = (sinx - cosx) ' = cosx + sinx 

y '(pi/4) = cospi/4 + sinpi/4 = √2/2 + √2/2 = 2√2/2 = √2 

Answer 2

It seems like you're providing an equation Y = sin(x) - cos(x) and a specific value x₀ = π/4. If you're looking to evaluate the equation at that particular value of x₀, I can help you with that.

Given the equation Y = sin(x) - cos(x), and x₀ = π/4, we can substitute the value of x₀ into the equation to find the corresponding value of Y:

Y(x₀) = sin(π/4) - cos(π/4)

Using the trigonometric values for π/4:

sin(π/4) = 1/√2 cos(π/4) = 1/√2

Substituting these values:

Y(x₀) = 1/√2 - 1/√2 Y(x₀) = 0

So, when x = π/4, Y = 0.