Question

1/(a^2b+ab^2) / 5/(a^2b^4-a^4b^2) при a = 0,1 b=0,9

Answer 1

Фоточка тебе в помощь ;)

Answer 2

Ответ:..............

Answer 3

To calculate the expression (1/(a^2b+ab^2)) / (5/(a^2b^4-a^4b^2)) with the given values a = 0.1 and b = 0.9, follow these steps:

Step 1: Substitute the given values into the expression: (1/(a^2b+ab^2)) / (5/(a^2b^4-a^4b^2)) = (1 / ((0.1)^2 * 0.9 + 0.1 * (0.9)^2)) / (5 / ((0.1)^2 * (0.9)^4 - (0.1)^4 * (0.9)^2))

Step 2: Evaluate the expressions within the parentheses: (1 / (0.01 * 0.9 + 0.1 * 0.81)) / (5 / (0.01 * 0.6561 - 0.0001 * 0.81))

Step 3: Simplify the expressions further: (1 / (0.009 + 0.081)) / (5 / (0.006561 - 0.000081))

Step 4: Calculate the values in the parentheses: (1 / 0.09) / (5 / 0.00648)

Step 5: Simplify the fractions: 11.1111 / 771.6049

Step 6: Divide the fractions: Result ≈ 0.0144

Therefore, when a = 0.1 and b = 0.9, the expression (1/(a^2b+ab^2)) / (5/(a^2b^4-a^4b^2)) evaluates to approximately 0.0144.