Question

(2b+b²)²+b²×(5-b)×(5+b)-4b×(b²-3)

Answer 1

Подробное решение на фото

Answer 2

4b^2+4b^3+b^4+25b^2-b^4-4b^3+12b=29b^2+12b

Answer 3

Let's simplify the expression step by step:

1. Expand the first term: (2b + b²)² = (2b + b²)(2b + b²) Using the FOIL method (First, Outer, Inner, Last): = 2b * 2b + 2b * b² + b² * 2b + b² * b² = 4b² + 2b³ + 2b³ + b⁴ = b⁴ + 4b³ + 4b²

2. Expand the second term: b² * (5 - b) = 5b² - b³

3. Expand the third term: (5 + b) * (5 - b) = 5 * 5 - 5b + b * 5 - b * b = 25 - 5b + 5b - b² = 25 - b²

4. Expand the fourth term: -4b * (b² - 3) = -4b³ + 12b

Now, we can put all the expanded terms together and simplify the expression:

(b⁴ + 4b³ + 4b²) + (5b² - b³) + (25 - b²) - (4b³ - 12b)

Combine like terms:

b⁴ + 4b³ + 4b² + 5b² - b³ + 25 - b² - 4b³ + 12b

Now, let's simplify further by combining the terms with the same powers of b:

(b⁴) + (4b³ - b³) + (4b² + 5b² - b²) + (12b) + (25)

Simplify the terms in parentheses:

b⁴ + 3b³ + 8b² + 12b + 25

So, the simplified expression is: b⁴ + 3b³ + 8b² + 12b + 25