Question

1) (a-b)² : (a-b)³= 2) (-(х)³)⁶ = 3) ((- 11³)² =

Answer 1

Пишу ответы, т.к. больше здесь писать, вроде, нечего.
1)1/(a-b)
2)x^18
3) 11^6

Answer 2

Let's solve each of the given expressions step by step:

1. (a - b)² : (a - b)³

Step 1: Simplify the expressions inside the brackets. (a - b)² = (a - b) * (a - b) = a² - 2ab + b² (a - b)³ = (a - b) * (a - b) * (a - b) = a³ - 3a²b + 3ab² - b³

Step 2: Divide (a - b)² by (a - b)³ (a² - 2ab + b²) / (a³ - 3a²b + 3ab² - b³)

Since both the numerator and denominator have a common factor of (a - b), we can cancel them out: = (a² - 2ab + b²) / (a³ - 3a²b + 3ab² - b³) = 1 / (a - b)

So the final result is 1 / (a - b).

2. (-(x)³)⁶

Step 1: Evaluate the expression inside the brackets. (-(x)³) = -x³

Step 2: Raise -x³ to the power of 6. (-x³)⁶ = -(x³)⁶ = -(x^18) = -x^18

So the result is -x^18.

3. ((-11³)²)

Step 1: Evaluate -11³. -11³ = -(11³) = -(11 * 11 * 11) = -1331

Step 2: Square -1331. (-1331)² = (-1331) * (-1331) = 1771561

So the result is 1771561.

Please note that in expressions involving powers, it's crucial to follow the order of operations (PEMDAS/BODMAS) to ensure correct calculations.