Question

6a/4a^2-b^2-3/2a+b при a=5 b=5

Answer 1

$\frac{6a}{4a^{2} -b^{2} } - \frac{3}{2a+b} = \frac{6a}{(2a-b)(2a+b)}- \frac{3}{2a+b} = \\ \\ \frac{6a-3(2a-b)}{(2a-b)(2a+b)} = \frac{6a-6a+3b}{(2a-b)(2a+b)} = \frac{3b}{(2a-b)(2a+b)}$

при  а=b=5

$\frac{3*5}{(2*5+5)(2*5-5)}= \frac{15}{15*5} = \frac{1}{5} =0,2$

Answer 2

To evaluate the expression (6a/4a^2 - b^2 - 3/2a + b) when a = 5 and b = 5, follow these steps:

1. Substitute the values of a and b into the expression.
2. Perform the calculations step by step.

Let's proceed with the calculations:

Step 1: Substitute the values of a and b (6 * 5) / (4 * 5^2) - 5^2 - 3 / (2 * 5) + 5

Step 2: Perform the calculations (30) / (4 * 25) - 25 - (3 / 10) + 5

Step 3: Continue simplifying 30 / 100 - 25 - 0.3 + 5

Step 4: More simplification 0.3 - 25 - 0.3 + 5

Step 5: Final calculation -24 + 5

Step 6: The result -19

So, when a = 5 and b = 5, the expression evaluates to -19.