Question

(x+2x+1)(x+2x)=12 (3х +1)-2 (3х +1)=8

Answer 1

(x+2x+1)(x+2x)=12
(3x+1) × 3x= 12
9x²+ 3x - 12 =0
Д= 9 + 432 = 441 = 21²
x1= (-3- 21 ) / 18 = -24 / 18= -4 / 3 
x2 = (-3+21) / 18 = 18/ 18 = 1
Ответ : -4/3 ; 1.


(3х +1)-2 (3х +1)=8
3x+1-6x-2=8
-3x=8-1+2
-3x= 9
x=-3
Ответ : -3.

Answer 2

(х²+1)(х+2х)=12
х³+2х³+х+2х=12
3х³+3х=12
х³+х=4
х(х²+1)=4
х=4 х=1

Answer 3

Let's solve the two equations step by step:

1. (x + 2x + 1)(x + 2x) = 12

First, simplify the expressions inside the parentheses:

3x(x + 2x) = 12

Now, distribute the 3x:

3x^2 + 6x = 12

Subtract 12 from both sides to set the equation to zero:

3x^2 + 6x - 12 = 0

Next, divide the entire equation by 3 to simplify it further:

x^2 + 2x - 4 = 0

Now, we have a quadratic equation. To solve it, we can use the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / 2a

where a = 1, b = 2, and c = -4.

x = (-2 ± √(2^2 - 4 * 1 * -4)) / 2 * 1

x = (-2 ± √(4 + 16)) / 2

x = (-2 ± √20) / 2

x = (-2 ± 2√5) / 2

Now, split it into two solutions:

1. x = (-2 + 2√5) / 2 = -1 + √5
2. x = (-2 - 2√5) / 2 = -1 - √5

2. (3x + 1) - 2(3x + 1) = 8

Let's simplify the expression:

3x + 1 - 6x - 2 = 8

Combine like terms:

-3x - 1 = 8

Add 1 to both sides:

-3x = 9

Finally, divide both sides by -3:

x = -3

So, the solutions to the two equations are:

1. x = -1 + √5
2. x = -1 - √5
3. x = -3