Question

3)xy-y (в квадрате)-8x+8 4)x (в 6 степени)-64

Answer 1

3)=(xy-y)+(-8x+8)=y(x-1)-8(x-1)=(x-1)(y-8)
4)=(x^3-8)(x^3+8)

Answer 2

To clarify, it seems like you have two mathematical expressions:

1. $3xy-y^2-8x+8$
2. $x^6-64$

Is there anything specific you would like to do with these expressions? Please let me know if you need help with simplifying, factoring, solving, or any other operations.