Question

Y=2cos3x-3sin2x+6 y=0 x=0 x=P/6 40б

Answer 1

Первое
второе нет решения

Answer 2

It seems like you want to find the value of the expression Y at different values of x. Let's proceed step by step:

1. Find Y when x = 0: To find Y when x = 0, substitute x = 0 into the expression for Y: Y = 2cos(3 * 0) - 3sin(2 * 0) + 6 Y = 2 - 0 + 6 Y = 8

So, when x = 0, Y = 8.

2. Find Y when x = π/6: To find Y when x = π/6, substitute x = π/6 into the expression for Y: Y = 2cos(3 * π/6) - 3sin(2 * π/6) + 6 Y = 2cos(π/2) - 3sin(π/3) + 6

Now, we need to know the exact values of cos(π/2) and sin(π/3): cos(π/2) = 0 sin(π/3) = √3 / 2

Now, substitute these values back into the equation: Y = 2 * 0 - 3 * (√3 / 2) + 6 Y = -3√3/2 + 6

So, when x = π/6, Y = -3√3/2 + 6.

3. Find Y when x = 40: Without knowing the unit of x (degrees or radians), it's not possible to provide an exact value for Y at x = 40. Please specify whether x is in degrees or radians.

If x = 40 degrees: Y = 2cos(3 * 40) - 3sin(2 * 40) + 6 Y = 2cos(120) - 3sin(80) + 6

To find the values of cos(120) and sin(80) either we need to use a calculator or trigonometric identities.

If x = 40 radians: Y = 2cos(3 * 40) - 3sin(2 * 40) + 6 Y = 2cos(120) - 3sin(80) + 6

Again, to find the values of cos(120) and sin(80) either we need to use a calculator or trigonometric identities.

Please provide additional information about the unit of x (degrees or radians) to proceed further.