Question

1) (2x-3)^2= ... 2) (3-4y)^2= ... Подробно распишите.

Answer 1

1) (2x - 3)² = (2x)² - 2 * 2x * 3 + 3² = 4x² - 12x + 9

2) (3 - 4y)² = 3² - 2 * 3 * 4y + (4y)² = 9 - 24y + 16y²

Answer 2

1) (2x-3)² = (2х)² - 2·2х·3 + 3² = 4х² - 12х + 9

2) (3-4y)² = 3² - 2·3·4у + (4у)² = 9 - 24у + 16у²

Answer 3

Sure, let's expand both expressions step by step:

1. Expanding (2x - 3)^2:

Step 1: Square the first term (2x)^2: (2x)^2 = 4x^2

Step 2: Multiply the first term by the second term and double it: 2 * (2x) * (-3) = -12x

Step 3: Square the second term (-3)^2: (-3)^2 = 9

Now, add all the results together: (2x - 3)^2 = 4x^2 - 12x + 9

2. Expanding (3 - 4y)^2:

Step 1: Square the first term (3)^2: (3)^2 = 9

Step 2: Multiply the first term by the second term and double it: 2 * (3) * (-4y) = -24y

Step 3: Square the second term (-4y)^2: (-4y)^2 = 16y^2

Now, add all the results together: (3 - 4y)^2 = 9 - 24y + 16y^2

So, the expanded forms are:

1. (2x - 3)^2 = 4x^2 - 12x + 9
2. (3 - 4y)^2 = 9 - 24y + 16y^2