Question

1) (х-9) (2х+7)=0 2)-17а+3=-3х+2

Answer 1

1) (x-9)(2x+7)=0
x-9=0; 2x+7=0
x=9; 2x=-7
x=9; x=-3.5
Ответ: х = 9; - 3.5

2) -17х+3=-3х+2
-17х+3х=2-3
-14х=-1
х=1/14
Ответ: х=1/14

Answer 2

To solve these equations, we'll find the values of the variables that satisfy each equation. Let's solve them step by step:

1. (х - 9)(2х + 7) = 0

To solve this equation, we'll use the zero-product property, which states that if the product of two factors is equal to zero, then at least one of the factors must be equal to zero. So, we set each factor equal to zero and solve for x:

Set the first factor (х - 9) equal to zero: х - 9 = 0

Add 9 to both sides to isolate x: х = 9

Set the second factor (2х + 7) equal to zero: 2х + 7 = 0

Subtract 7 from both sides to isolate x: 2х = -7

Divide both sides by 2: х = -7/2

So the solutions to the equation are x = 9 and x = -7/2.

2. -17a + 3 = -3x + 2

It seems that this equation involves both 'a' and 'x', but we can still try to solve it. However, we need one more equation that relates 'a' and 'x' to find a unique solution. As it stands, we cannot solve for both variables simultaneously.

If you have another equation that relates 'a' and 'x', please provide it, and I'll be happy to help you solve the system of equations. Otherwise, we won't be able to find a unique solution for 'a' and 'x' with this single equation.