Question

10/√-x-5напишите подробнее, как решать

Answer 1

Нельзя корень извлекать из отрицательное чисел . нет решения .

Answer 2

To solve the expression 10/√(-x) - 5, we need to follow these steps:

Step 1: Identify the domain The expression involves a square root, and square roots of negative numbers are not defined in the real number system. Therefore, to ensure the expression is valid, we must find the domain for which the expression is defined. The radicand (the value inside the square root) must be non-negative for real numbers.

For √(-x) to be defined, -x ≥ 0. Solving for x: -x ≥ 0 x ≤ 0

So the domain of the expression is x ≤ 0.

Step 2: Substitute x in the expression Now that we have the domain, we can substitute x with different values that satisfy x ≤ 0 and find the corresponding results.

Let's plug in some values for x:

1. If x = 0: 10/√(-0) - 5 10/√0 - 5

The expression is not defined at x = 0 because the denominator becomes 0, which is not allowed in the real number system.

2. If x = -1: 10/√(-(-1)) - 5 10/√1 - 5 10/1 - 5 10 - 5 Result: 5

3. If x = -4: 10/√(-(-4)) - 5 10/√4 - 5 10/2 - 5 5 - 5 Result: 0

Step 3: Summary of results From the above calculations, we can see that the expression is defined and takes the following values for the corresponding values of x in the domain x ≤ 0:

x = -1, result = 5 x = -4, result = 0

Keep in mind that the expression is undefined at x = 0 and for any other positive value of x since the square root of a negative number is not valid in the real number system.

Thus, the solution to the expression 10/√(-x) - 5 in the domain x ≤ 0 is as described above.