Question

Решите 2^4*(2^2)-^3/2^-5=

Answer 1

$2^4*(2^2)^{-3}/2^{-5}=2^4*2^{-6}*2^{5}=8$

Answer 2

To solve the expression, let's follow the order of operations (PEMDAS/BODMAS), which stands for Parentheses/Brackets, Exponents/Orders, Multiplication and Division (from left to right), and Addition and Subtraction (from left to right).

The given expression is: 2^4 * (2^2) - 3 / 2^(-5)

Step 1: Simplify the exponents: 2^4 = 2 * 2 * 2 * 2 = 16 2^2 = 2 * 2 = 4 2^(-5) = 1 / 2^5 = 1 / 32

So, the expression becomes: 16 * 4 - 3 / (1/32)

Step 2: Perform the division: 3 / (1/32) = 3 * 32 = 96

Now, the expression becomes: 16 * 4 - 96

Step 3: Perform the multiplication: 16 * 4 = 64

Final result: 64 - 96 = -32

Therefore, the solution to the expression is -32.