Question

X^4-5x^2+49=0 дискриминант решите Срочно

Answer 1

${x}^{4} - 5 {x}^{2} + 49 = 0 \\ {x}^{2} = t \\ {t}^{2} - 5t + 49 = 0 \\ d = 25 - 196 = - 159$
Ответ : не имеет решений x€∅

Answer 2

To find the discriminant of the quadratic equation $x^4 - 5x^2 + 49 = 0$, we first need to recognize that this equation is in the form of a quadratic equation in terms of $x^2$. We can rewrite it as:

$x^4 - 5x^2 + 49 = 0$

Let's define $y = x^2$, so the equation becomes:

$y^2 - 5y + 49 = 0$

Now, the quadratic equation is $y^2 - 5y + 49 = 0$, and the discriminant is given by $D = b^2 - 4ac$, where the quadratic equation is in the form $ay^2 + by + c = 0$.

In our case, $a = 1$, $b = -5$, and $c = 49$. Now we can calculate the discriminant:

$D = (-5)^2 - 4 \cdot 1 \cdot 49$ $D = 25 - 196$ $D = -171$

The discriminant of the equation $x^4 - 5x^2 + 49 = 0$ is $-171$.