Question

6а⁴-2а(3а²+7) ху(х-у)-2ху(х+у) 10ху+15у² 2у⁴-6у^7

Answer 1

6а^4-2а(3а^2+7)ху(х-у)-2ху(х+у)=2(3а^4-а(3а^2+7)ху(х-у)-ху(х+у))=2(3а^4+(-3а^3ху -7аху)(х-у)-х^2у-ху^2)=2(3а^4-3а^3х^2у+3а^3ху^2-7ах^2 у+7аху^2-х^2у-ху^2)

Answer 2

To simplify the given expression, let's combine like terms:

6а⁴ - 2а(3а² + 7) ху(х - у) - 2ху(х + у) + 10ху + 15у² - 2у⁴ - 6у^7

Step 1: Distribute the -2a to the terms inside the parentheses: 6а⁴ - 6а³y - 14аy ху(х - у) - 2ху(х + у) + 10ху + 15у² - 2у⁴ - 6у^7

Step 2: Distribute the ху to the terms inside the parentheses: 6а⁴ - 6а³y - 14аy х² + 14аy² ху - 2х²y² - 2ху² + 10ху + 15у² - 2у⁴ - 6у^7

Step 3: Combine like terms: 6а⁴ - 6а³y - 14аy х² + 14аy² ху - 2х²y² - 2ху² + 10ху + 15у² - 2у⁴ - 6у^7

That's the simplified form of the given expression.