Question

3у² - 2ху = 28 ФИГУРНАЯ СКОБКА х + 3у = -2

Answer 1

x= -3y -2

3y² +6y²+4y = 28

9y²+4y-28 = 0

(y+2)(9y-14) = 0

y₁ = -2

y₂ = 14/9 = 1 5/9

x₁ = 6-2=4

x₂ = -14/3-2 = -6 2/3

Answer 2

To solve the system of equations, we can use the method of substitution or elimination. Let's use the substitution method to find the values of x and y.

Given system of equations:

1. 3у² - 2ху = 28
2. х + 3у = -2

Step 1: Solve one of the equations for one variable in terms of the other variable. Let's solve equation 2 for x: x = -2 - 3y

Step 2: Substitute the expression obtained in Step 1 into the other equation (equation 1) and solve for y. 3y² - 2(-2 - 3y)y = 28 3y² + 4y + 28 = 28

Step 3: Simplify the equation and bring all terms to one side: 3y² + 4y + 28 - 28 = 0 3y² + 4y = 0

Step 4: Factor out the common term, which is y in this case: y(3y + 4) = 0

Step 5: Set each factor to zero and solve for y:

1. y = 0
2. 3y + 4 = 0 3y = -4 y = -4 / 3

Step 6: Now that we have the values of y, we can find the corresponding values of x using equation 2: For y = 0: x = -2 - 3(0) x = -2

For y = -4/3: x = -2 - 3(-4/3) x = -2 + 4 x = 2

So, the solutions to the system of equations are: x = -2, y = 0 x = 2, y = -4/3