Question

X+6 + 10 3 X+5 X^2 -25= 2

Answer 1

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Answer 2

To solve the equation, let's first rearrange it and put all terms on one side to form a quadratic equation. Then we can use the quadratic formula to find the values of "x."

The given equation is:

x + 6 + 10(3x + 5x^2) - 25 = 2

Now, simplify the equation:

x + 6 + 30x + 50x^2 - 25 = 2

Combine like terms:

50x^2 + 31x - 17 = 2

Now, the equation is in the form of ax^2 + bx + c = 0, where: a = 50 b = 31 c = -17 - 2 = -19

We can use the quadratic formula to find the solutions for x:

x = (-b ± √(b^2 - 4ac)) / 2a

Substitute the values:

x = (-(31) ± √(31^2 - 4 * 50 * (-19))) / 2 * 50

Calculate the discriminant:

Discriminant (Δ) = b^2 - 4ac Δ = 31^2 - 4 * 50 * (-19) Δ = 961 + 3800 Δ = 4761

Now, find the square root of the discriminant:

√Δ = √4761 √Δ = 69

Now, we have:

x = (-(31) ± 69) / 100

Now, let's find the two solutions for "x":

1. x = (-(31) + 69) / 100 x = 38 / 100 x = 0.38

2. x = (-(31) - 69) / 100 x = -100 / 100 x = -1

So, the solutions for the equation are x = 0.38 and x = -1.