Question

(√10-1) во 2 степени

Answer 1

(√10)^2-2*1*√10+1^2 = 10-2√10+1 =11-2√10

Answer 2

$( \sqrt{10} - 1) ^{2} = 10 - 2 \sqrt{10} + 1 = 11 - 2 \sqrt{10}$

Answer 3

To calculate the expression (√10 - 1)², follow these steps:

Step 1: Calculate the value inside the parentheses (√10 - 1). Step 2: Square the result obtained from Step 1.

Step 1: √10 - 1 = √10 - 1 * √10 / √10 = (√10 * √10 - √10) / √10 = (10 - √10) / √10 = (10/√10) - (√10/√10) = (10/√10) - 1

Now, to rationalize the denominator (√10) in the first term, we multiply both the numerator and the denominator by √10: (10/√10) - 1 = (10/√10) * (√10/√10) - 1 = 10√10/10 - 1 = √10 - 1

Step 2: (√10 - 1)² = (√10 - 1) * (√10 - 1) = √10 * √10 - √10 - √10 + 1 = 10 - 2√10 + 1 = 11 - 2√10

Therefore, (√10 - 1)² is equal to 11 - 2√10.