Question

(3x+4)^2=(3x-2)(2x+3)

Answer 1

Ответ:

Объяснение:

(3x+4)^2=(3x-2)(2x+3)

9x² + 24x + 16 = 6x²-4x+9x-6

3x² + 19x + 22 = 0

D = 19²-4·3·22 = 97

$x_{12} = \frac{-19±\sqrt{97} }{6}$

Answer 2

Ты як гонишь? Это же легко

Answer 3

To determine whether the equation (3x + 4)^2 = (3x - 2)(2x + 3) is true for all values of x, we need to simplify both sides of the equation and check if they are equivalent.

Let's start by expanding both sides of the equation:

Left-hand side (LHS): (3x + 4)^2 = (3x + 4)(3x + 4) = 9x^2 + 12x + 12x + 16 = 9x^2 + 24x + 16

Right-hand side (RHS): (3x - 2)(2x + 3) = 3x * 2x + 3x * 3 + (-2) * 2x + (-2) * 3 = 6x^2 + 9x - 4x - 6 = 6x^2 + 5x - 6

Now, we have:

LHS: 9x^2 + 24x + 16 RHS: 6x^2 + 5x - 6

Now, let's compare the two sides:

9x^2 + 24x + 16 ≠ 6x^2 + 5x - 6

Since the left-hand side (LHS) is not equal to the right-hand side (RHS) for all values of x, the original equation (3x + 4)^2 = (3x - 2)(2x + 3) is not true for all x.