Question

Сократите дробь c2+2c/c+2​

Answer 1

$\frac{6}{2}=\frac{2*3}{2}=3$

Так же и с переменными, только на ноль делить нельзя.

$\frac{c^2+2c}{c+2}=\frac{c(c+2)}{c+2};\\\left \{ {{c+2\neq0} \atop {c}} \right.\\\left \{ {{c\neq-2} \atop {c}} \right.$

Остаётся просто с, но при условии, что с≠ -2

Answer 2

вот решение этого примера..

Answer 3

To simplify the fraction (c^2 + 2c) / (c + 2), we can factor the numerator and then cancel out common factors with the denominator. Here's the step-by-step process:

Step 1: Factor the numerator (c^2 + 2c). c^2 + 2c = c(c + 2).

Step 2: Rewrite the original fraction using the factored numerator. (c^2 + 2c) / (c + 2) = c(c + 2) / (c + 2).

Step 3: Cancel out the common factor (c + 2) from the numerator and denominator. The (c + 2) term in the numerator and denominator cancels out, leaving us with: c.

So, the simplified form of the fraction is just c.