Question

А)(y-4)²б)(7x+a)²в)(в+3)(в-3)г)(5у-2х)(5у+2х​)

Answer 1

а)(y-4)²=(y)²-2*y*4+(4)²=y²-8y+16

б)(7x+a)²=(7x)²+2*7x*a+(a)²=49x²+14ax+a²

в)(b+3)(b-3)=(b)²-(3)²=b²-9

г)(5y-2x)(5y+2x)=(5y)²-(2x)²=25y²-4x²

Answer 2

Let's expand each expression:

а) $(y-4)^2$ To expand this expression, we can use the formula $(a - b)^2 = a^2 - 2ab + b^2$. In this case, $a = y$ and $b = 4$. $(y-4)^2 = y^2 - 2y \cdot 4 + 4^2 = y^2 - 8y + 16$

б) $(7x + a)^2$ To expand this expression, we use the same formula, with $a = 7x$ and $b = a$. $(7x + a)^2 = (7x)^2 - 2 \cdot 7x \cdot a + a^2 = 49x^2 - 14ax + a^2$

в) $(в + 3)(в - 3)$ This is the difference of squares, which can be expanded using the formula $a^2 - b^2 = (a + b)(a - b)$. In this case, $a = в$ and $b = 3$. $(в + 3)(в - 3) = в^2 - 3^2 = в^2 - 9$

г) $(5у - 2х)(5у + 2х)$ This is also the difference of squares. Here, $a = 5у$ and $b = 2х$. $(5у - 2х)(5у + 2х) = (5у)^2 - (2х)^2 = 25у^2 - 4х^2$

Please note that in expressions (б) and (г), I used the variable $a$ instead of the Cyrillic letter "а" to avoid confusion with the number "1." If you meant the Cyrillic letter "а," you can replace it accordingly.