Question

(3a+b)^2-(a+b)(a-b) при a=2 b=1/2

Answer 1

(3a+b)^2-(a+b)(a-b)=

=9a^2+6ab+b^2-(a^2-b^2)=

=9a^2+6ab+b^2-a^2+b^2=

=8a^2+6ab+2b^2=

при а=2 и b=0.5

=8*2^2+6*2*0.5+2*0.5^2=

=8*4+6+2*0.25=

=32+6+0.5=

=38.5

Answer 2

Ответ:

38,5

Объяснение:

9а²+6ab+b²-a²+b²=8a²+6ab+2b²=2(4a²+3ab+b²)

2*(4²+3*2*1/2+(1/2)²)=2*(16+3+1/4)=2*19 1/4=2*77/4=77/2=38 1/2=38,5

Answer 3

To evaluate the expression (3a+b)^2 - (a+b)(a-b) when a=2 and b=1/2, we simply substitute the values of a and b into the expression and perform the calculations step by step.

Step 1: Substitute the values of a and b. a = 2 b = 1/2

Step 2: Evaluate (3a+b)^2 (3a + b)^2 = (3*2 + 1/2)^2 = (6 + 1/2)^2 = (6.5)^2 = 42.25

Step 3: Evaluate (a+b)(a-b) (a + b)(a - b) = (2 + 1/2)(2 - 1/2) = (2.5)(1.5) = 3.75

Step 4: Evaluate the final expression. (3a+b)^2 - (a+b)(a-b) = 42.25 - 3.75 = 38.5

So, when a=2 and b=1/2, the value of the expression (3a+b)^2 - (a+b)(a-b) is 38.5.