Question

2-2x^2/4x^2-8x+4 распишите решение

Answer 1

2-2x^2/4x^2-8x+4= (2 (1-х²)) / (2 (2х²-4х+2)) = ((1-х) (1+х)) / (2 (х²-2х+1))= (- (х-1) (1+х)) / (2 (х-1)²= ((-1) (1+х)) / (2 (х-1)) =-(1+х) / (2х-2)

Answer 2

To simplify the expression, we need to perform the following steps:

Step 1: Factor the expressions in the numerator and denominator. Step 2: Cancel out any common factors. Step 3: Reduce the fraction to its simplest form.

Given expression: (2 - 2x^2) / (4x^2 - 8x + 4)

Step 1: Factor the numerator and denominator: Numerator: 2 - 2x^2 Numerator can be factored as the difference of squares: Numerator = 2 - 2x^2 = 2(1 - x^2) = 2(1 - x)(1 + x)

Denominator: 4x^2 - 8x + 4 Denominator can be factored as well: Denominator = 4x^2 - 8x + 4 = 4(x^2 - 2x + 1) = 4(x - 1)(x - 1)

Step 2: Cancel out any common factors. Now, let's cancel out the common factors between the numerator and denominator: (2(1 - x)(1 + x)) / (4(x - 1)(x - 1))

Step 3: Reduce the fraction to its simplest form. Since (x - 1) appears in both the numerator and denominator, we can cancel it out: (2(1 + x)) / 4(x - 1)

Now, we can further simplify the expression: (2 + 2x) / 4(x - 1)

Finally, we can simplify the fraction by dividing both the numerator and denominator by their greatest common divisor (GCD), which is 2: (1 + x) / 2(x - 1)

So, the simplified form of the expression is (1 + x) / 2(x - 1).