Question

(5v+u^5)⋅(25v^2−5vu^5+u^10).

Answer 1

Ответ:

Объяснение:

(5v+u⁵)⋅(25v²−5v*u⁵+u¹⁰)=(5v+u⁵)⋅((5v)²−5v*u⁵+(u⁵)²)=

=(5v)³+(u⁵)³=125v³+u¹⁵.

Answer 2

Ответ:

Объяснение:

$(5v+u^5)(25v^2-5vu^5+u^{10})=125v^3-25v^2u^5+5v^{11}+25v^2y^5-5vu^{10}+v^{10}u^5=\\=125v^3+5v^{11}-5vu^{10}+v^{10}u^{5}$

Answer 3

To simplify the expression (5v+u^5)⋅(25v^2−5vu^5+u^10), we can use the distributive property of multiplication over addition/subtraction.

Let's break down the expression step by step:

Step 1: Distribute 5v over the terms inside the second parentheses: (5v) * 25v^2 + (5v) * (-5vu^5) + (5v) * u^10

Simplified step 1: 125v^3 - 25v^2u^5 + 5vu^10

Step 2: Distribute u^5 over the terms inside the second parentheses: (u^5) * 25v^2 + (u^5) * (-5vu^5) + (u^5) * u^10

Simplified step 2: 25u^5v^2 - 5u^10v^1 + u^15

Step 3: Combine the results from step 1 and step 2: 125v^3 - 25v^2u^5 + 5vu^10 + 25u^5v^2 - 5u^10v^1 + u^15

Finally, we can group like terms: (125v^3 + 25u^5v^2) + (-25v^2u^5 - 5u^10v^1) + (5vu^10 + u^15)

So, the simplified expression is: 125v^3 + 25u^5v^2 - 25v^2u^5 - 5u^10v^1 + 5vu^10 + u^15

Note: The order of the terms does not affect the simplification, but it's good practice to arrange them in a standard form.