Question

|2x-y-3|+(x+3y-5)^2=0

Answer 1

Ответ :

{ | 2х - у - 3 | = 0

{ (х + 3у - 5)^2 = 0

{ 2х - у - 3 = 0

{ х + 3 у - 5 = 0

{ 6х + 3у - 9 = 0

{ 2х - у - 3 = 0

{ 7х - 14 = 0

{ у = 2х - 3

{ х = 2

{ у = 1

Ответ : (2 ; 1).

Рада помочь, если не трудно, пожалуйста добавьте этот ответ в "Лучший", за ранее спасибо (^-^).

Answer 2

To solve the equation |2x - y - 3| + (x + 3y - 5)^2 = 0, we need to find the values of x and y that satisfy the equation.

Let's analyze the equation step by step:

Step 1: Deal with the absolute value expression. The absolute value of a real number is always non-negative, so the term |2x - y - 3| will be non-negative for any values of x and y. In order for the sum of two non-negative values to be zero, both terms must be zero. So, we have:

1. 2x - y - 3 = 0 (The expression inside the absolute value is positive) or
2. -(2x - y - 3) = 0 (The expression inside the absolute value is negative)

Step 2: Solve the two equations.

1. 2x - y - 3 = 0: Solving for y: y = 2x - 3

2. -(2x - y - 3) = 0: Solving for y: y = -2x + 3

Now we have two linear equations relating x and y. We can proceed to find the values of x and y that satisfy both equations simultaneously.

Step 3: Equate the expressions for y from both equations.

Since both equations are equal to y, we can equate them:

2x - 3 = -2x + 3

Step 4: Solve for x.

4x = 6 x = 6 / 4 x = 3/2

Step 5: Substitute x back into one of the equations to find y.

Using y = 2x - 3: y = 2 * (3/2) - 3 y = 3 - 3 y = 0

So, the solution to the equation |2x - y - 3| + (x + 3y - 5)^2 = 0 is x = 3/2 and y = 0.