Question

(a²-9)²/(3-a)³ сократить​

Answer 1

Объяснение:

$\frac{(a {}^{2} - 9) {}^{2} }{(3 - a) {}^{3} } \\ \\ \frac{((a - 3) \times (a + 3)) {}^{2} }{( - (a - 3)) {}^{3} } \\ \\ \frac{(a + 3) {}^{2} }{ - (a - 3)} \\ \\ - \frac{a {}^{2} + 6a + 9 }{a - 3}$

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Answer 2

Ответ:

(а²+6а+9)/(а-3).

Объяснение:

(a²-9)²/(3-a)³ = (a-3)²•(а+3)²/(-1•(а-3)³) = (а+3)²/(-1•(а-3))= (а+3)²/(3-а) = (а²+6а+9)/(3-а).

Answer 3

To simplify the expression $\frac{(a^2-9)^2}{(3-a)^3}$, we can start by factoring the numerator and denominator.

Step 1: Factor the numerator The numerator $(a^2-9)^2$ can be factored as a difference of squares: $(a^2-9)^2 = (a^2-3^2)^2 = (a+3)(a-3)^2$

Step 2: Factor the denominator The denominator $(3-a)^3$ can be factored as well: $(3-a)^3 = -(a-3)^3$

Now, the expression becomes: $\frac{(a+3)(a-3)^2}{-(a-3)^3}$

Step 3: Cancel out common factors We can see that there is a common factor $(a-3)^2$ in the numerator and denominator. We can cancel it out: $\frac{(a+3)\cancel{(a-3)^2}}{-\cancel{(a-3)^2}(a-3)}$

Step 4: Simplify further Now, we have: $\frac{a+3}{-(a-3)}$

Step 5: Final result To make the expression easier to read, we can distribute the negative sign in the denominator: $\frac{a+3}{3-a}$

So, the simplified form of the expression is $\frac{a+3}{3-a}$.